Harnessing Nuclear Radiations!

e=h.nue

e=(6.623×10^-34 Js)(10^19 1/s) 

e= 6.623×10-15 J is the energy of a gamma radiation that’s considered the most hazardous to us humans or any living beings. And, that’s not false. But is left right there for many years although we learned that energy can be converted from one form to another but can neither be created or destroyed.
At times it becomes confusing to define the word CREATE because, anything that we do not create is not created by us. In the case off a nuclear gamma radiation we didn’t even know that such a small Atom contains that much energy that we can be scared of haha or in other words we identified it as a form of energy tbh. And, that’s all happened. From Gita we understand that everything around us is energy. If we find harmony with the energy around us, we thrive. TOGETHER. Which is very important. Getting back to the topic,

That’s e=6.623×10^-15 J from one Gamma radiation. 

And, if we consider a light bulb of 60 Watts, which means it burns 60 Watts energy per second while it’s ON.

Right? Not sure. But it doesn’t really matter how accurate we are in the definition of the energy unit, as we are trying to understand a bigger picture of the energy spectrum.

If the numbers aforementioned can be referred in the following way,

E required to light a 60 W bulb up for 1 second would be 60 J,

Some Yx6.623×10^-15 J = 60 J

Which implies Y = 60/(6.623×10^-15) =~ 10^(15+1) assuming that 60/6.623 ~= 9

That is, Y = 9×10^15, which means that, 9×10^15 gamma particles, each with a frequency of 10^19 cycles per second.

Let’s use Y to find the value of e that would further help us find the number of gamma radiations needed to light a bulb up.

And, then we can imagine the magnitude of radiations that are emitted from a nuclear reaction or a radioactive element with an unstable nucleus and then there is a plethora of these elements with varied half lives 🙂

Therefore, energy e required to light a 60 W bulb up for 1 second is, 

Total energy E = 9×10^15 gamma photons with 10^-15J of energy per particle
Therefore, E = ((60/6.623)x10^15) x (6.623×10^-15J)) =
((60/6.623)x10^15) x (6.623x10^-15J)) = 60J
Is this a high number to achieve?

Understanding the fact that, these energies are also streams of radiations emitted and not just energy particles makes it a more omni present energy particle that need not be searched for and can just receptor sensors to collect these radiated photons and use them to create light energy by transforming a photon to light.